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Can Anyone Help With Algebra?

08.26.2010 · Posted in Home

Can anyone tell me how to solve these two problems?
-7 < 9x + 2 < 11
The length of a rectangular garden is 7 feet longer than its width. The perimeter of the garden is 38 feet.



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5 Responses to “Can Anyone Help With Algebra?”

  1. -7 < 9x + 2 < 11
    -9 < 9x < 9
    -1 < x < 1
    l – 7 = w
    2l + 2w = 38
    2l + 2l – 14 = 38
    4l = 52
    l = 13 feet
    w = 6 feet

  2. -7 < 9x + 2 < 11
    -7 -2 < 9x + 2-2 < 11-2 //// subtract 2 from each
    -9 < 9x < 9 ///// divide each term by 9
    -1 < x < 1

  3. -7 < 9x + 2 < 11
    -7-2 < 9x < 11-2
    -9 < 9x < 9
    -1 < x < 1
    L = W+7
    2(L+W) = 38
    2(W+7 + W) = 38
    2W + 7 = 19
    2W = 19-7 = 12
    W = 6
    L = 6+7 = 13
    Length = 13 feet
    Width = 6 feet

  4. -9<9x<9
    -1 2(7+x)+2*x=38
    4x=28
    x=7 : width
    length = 14

  5. In the first one, I’d subtract 2 from each part and then divide everything by 9:
    -9 < 9x < 9
    -1< x < 1
    x = 0
    In the second one, I’d use the equation for perimeter: p = 2l + 2w.
    Remember that the length = (w + 7), and substitute that for length in the equation:
    38 = 2(w + 7) + 2w
    38 = 2w + 14 + 2w
    38 = 4w + 14
    24 = 4w
    6 = w
    That means that the length is 13.
    ANSWERS:
    x = 0
    Length = 13 width = 6

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